Question

find the acceleration due to gravity at a height of R/3 from the surface of earth where R is the radius of Earth​

Answer 1

the answer is g^2(1+re/2*re)^2=

g(1+1/2)^2= 4/9 g

w= mg^2

=mx 4/9 g =4/9 mg

4/9 w

4/9*63=28 N