Question

Factorise
6(2a-3b)^2-35(2a-3b)-6

Answer 1

Answer:

$\red {6(2a-3b)^{2} - 35(2a-3b) - 6 }$

$\green {= (2a-3b-6)(12a-18b+1)}$

Step-by-step explanation:

$6(2a-3b)^{2} - 35(2a-3b) - 6$

/* Splitting the middle term,we get

$= 6(2a-3b)^{2} - 36(2a-3b) + 1(2a-3b) - 6 \\= 6(2a-3b) [(2a-3b) - 6] + 1[(2a-3b)-6 ] \\= (2a-3b-6)[6(2a-3b)+1]\\= (2a-3b-6)(12a-18b+1)$

Therefore.,

$\red {6(2a-3b)^{2} - 35(2a-3b) - 6 }$

$\green {= (2a-3b-6)(12a-18b+1)}$

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