Question

plzz solve past...........​

Answer 1

sin(A + 36°) = cosA

sin(A + 36°) = sin(90° - A) ... cosA = sin(90° - A)

A + 36° = 90° - A

2A = 54°

A = 27°

Answer 2

Answer:

C.27

Step-by-step explanation:

Since sinθ= cos(90-θ)

So, sin(θ+36) = cosθ => cos(90-θ-36) = cosθ

=> 90-36- θ= θ

=>54= θ+θ

=>54/2=θ

=>27=θ