Math, asked by ms1763334, 1 month ago

factorise : 6( x- y)2 - x + y - 15. (step by step explanation please)​

Answers

Answered by mansinhmori24904
0

Answer:

The expression is 6(x-y)^2-x+y-156(x−y)

2

−x+y−15 and factorise it.

TO FACTORISE :

The given expression is 6(x-y)^2-x+y-156(x−y)

2

−x+y−15

SOLUTION :

Given that the expression is 6(x-y)^2-x+y-156(x−y)

2

−x+y−15

First factorising the given expression we have that,

That is now solving the given expression as below:

6(x-y)^2-x+y-156(x−y)

2

−x+y−15

By using the algebraic identity :

(a-b)^2=a^2-2ab+b^2(a−b)

2

=a

2

−2ab+b

2

=6(x^2-2xy+y^2)-x+y-15=6(x

2

−2xy+y

2

)−x+y−15

By using the Distributive property :

a(x+y+z)=ax+ay+az

=6(x^2)+6(-2xy)+6(y^2)-x+y-15=6(x

2

)+6(−2xy)+6(y

2

)−x+y−15

=6x^2-12xy+ 6y2-x + y - 15=6x

2

−12xy+6y2−x+y−15

=6x(x-2y)-(x+15)+y(6y+1)=6x(x−2y)−(x+15)+y(6y+1)

∴ 6(x-y)^2-x+y-15=6x(x-2y)-(x+15)+y(6y+1)6(x−y)

2

−x+y−15=6x(x−2y)−(x+15)+y(6y+1)

∴ These groups have no common factor.

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