Question

factorise 64 m^6- n^6​

Answer 1

STEP 1 :

Equation at the end of step 1

26m6 - n6

STEP 2 :

Trying to factor as a Difference of Squares:

2.1 Factoring: 64m6-n6

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 64 is the square of 8

Check : m6 is the square of m3

Check : n6 is the square of n3

Factorization is : (8m3 + n3) • (8m3-n3)

Answer 2

Step-by-step explanation:

$(2m - n) {}^{6}$

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