Factorise 64 (p – q)^3 – 27(x + y)^3
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Ans:- 64 (p – q)^3 – 27(x + y)^3
= let (p – q) = x and (x + y) = z
= 64x^3 - 27z^3
= (8x)^3 - (9z)^3
= (8x - 9z) (64x^2 + 72xz + 81z^2)
here is your answer
hope it will help you
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