Question

Factorise:
64 − x ^2 − y^ 2 − 2xy
(Please answer it ASAP, and only put accurate answers, else i shall report your answer)

Answer 1

Answer:

-(x + y - 8)(x + y + 8).

Step-by-step explanation:

Factor: 64 − x ^2 − y^ 2 − 2xy

Now x^2 + y^2 + 2xy = (x + y)^2 so

- x^2 - y^2 - 2xy = - (x + y)2

So we can write the original expression as:

- [(x + y)^2 - 64]

By the difference of 2 squares  (a^2 - b^2 = (a - b)(a + b)):-

this = -(x + y - 8)(x + y + 8).