Question

Factorise 64a³-27b³-144a²b+108ab² using x³+y³=(x+y) (x²-xy+y²)

Answer 1

Answer:

$= {64a}^{3} - {27b}^{3} - 3(18ab)(4a - 3b) \\\\= {(4a)}^{3} - {(3b)}^{3} - 3(2a)(3b)(4a - 3b) \\\\ = {(4a - 3b)}^{3}$

Step-by-step explanation:

you use only this formula