Question

factorise:64a⁸b⁸-36a²b²​

Answer 1

Answer:

$\red {64a^{8} b^{8} - 36a^{2}b^{2}}$

$\green { =4a^{2}b^{2} (4a^{3}b^{3} - 3)(4a^{3}b^{3} + 3)}$

Step-by-step explanation:

$64a^{8} b^{8} - 36a^{2}b^{2}$

$= 4a^{2}b^{2} ( 16a^{6}b^{6} - 9)$

$= 4a^{2}b^{2} [ (4a^{3}b^{3})^{2} - 3^{2}]$

$= 4a^{2}b^{2} (4a^{3}b^{3} - 3)(4a^{3}b^{3} + 3)$

$\boxed {\pink { x^{2} - y^{2} = (x-y)(x+y)}}$

Therefore.,

$\red {64a^{8} b^{8} - 36a^{2}b^{2}}$

$\green {=4a^{2}b^{2} (4a^{3}b^{3} - 3)(4a^{3}b^{3} + 3)}$

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Answer 2

Answer:

64a⁸b⁸-36a²b²

We have to take common no. among these.

4a²b² (16a⁶b⁶-9)

4a²b²{(4a³b³)²-3²}

Here we will use the formula.

$a {}^{2} - b {}^{2} = (a + b) {}^{2} (a - b) {}^{2}$

4a²b²(4a³b³-3)(4a³b³+3)