factorise 64x3-1/8y3
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Answer:-
64x³-1/8y³=>(4x)³-(1/2y)³
[a³-b³=(a-b) (a²+b²+ab)
(4x-1/2y)[(4x)²+(1/2y)²+4x×1/2y]
(4x-1/2y)(16x²+1/4y²+2xy)
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if iam correct please mark me as brainlist
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