Question

factorise 64x⁴-343 using identities​

Answer 1

Answer:

ig your question is a bit wrong. It should be 64x³-343

Step-by-step explanation:

64x³-343

(4x)³-7³

using the identity a³-b³

a=4x. b=7

(a-b)(a²+b²+ab)

(4x-7)(16x²+49+28x)