factorise 64x⁴-343 using identities
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Answer:
ig your question is a bit wrong. It should be 64x³-343
Step-by-step explanation:
64x³-343
(4x)³-7³
using the identity a³-b³
a=4x. b=7
(a-b)(a²+b²+ab)
(4x-7)(16x²+49+28x)
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