Question

Factorise : 6a^2 + 19a + 10 please anyone tell.​

Answer 1

Use the sum-product pattern

62+19+10

6a^{2}+{\color{#c92786}{19a}}+106a2+19a+10

62+15+4+10

6a^{2}+{\color{#c92786}{15a}}+{\color{#c92786}{4a}}+106a2+15a+4a+10

2

Common factor from the two pairs

62+15+4+10

6a^{2}+15a+4a+106a2+15a+4a+10

3(2+5)+2(2+5)

3a(2a+5)+2(2a+5)3a(2a+5)+2(2a+5)

3

Rewrite in factored form

3(2+5)+2(2+5)

3a(2a+5)+2(2a+5)3a(2a+5)+2(2a+5)

(3+2)(2+5)

(3a+2)(2a+5)(3a+2)(2a+5)

Solution

(3+2)(2+5)

Step-by-step explanation:

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Answer 2

$\bold{\red{Question}}$

Factorise 6a² + 19a + 10

$\bold{Solution}$

$\bold{6a² + 19a + 10}$

$\bold{6a²+15a+4a+10}$

$\bold{3a(2a+5)+(2a+5)}$

$\bold{\red{(3a+2)(2a+5)}}$

hope it helps ☺️☺️