Question

*Factorise 6a ki power 5 -96a*​

Answer 1

${6a}^{5} - 96a$

$6a( {a}^{4} - 16)$

using identity 3 ,

$( {a}^{4} - 16) = ({a}^{2} + 4)( {a}^{2} - 4)$

Hence ,

the factors are

$6a \: ( {a}^{2} + 4) \: ( {a}^{2} - 4)$

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