Question

Factorise:
6a² + 17ab - 42
Please answer this in 8th grade format

Answer 1

Answer:

We have, 6a2 + 17ab – 3b2 The coefficient of a2 is 6 The coefficient of a is 17b Constant term is -3b2 So, we express the middle term 17ab as 18ab – ab 6a2 +17ab– 3b2 = 6a2 + 18ab – ab – 3b2 = 6a (a + 3b) – b (a + 3b) = (6a – b) (a + 3b)Read more on Sarthaks.com - https://www.sarthaks.com/662777/resolve-the-quadratic-trinomials-into-factors-6a-2-17ab-3b-2