Factorise
6ab-(b)2+12ac-2bc
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Answer:
(6a-b),(b+2c)
Step-by-step explanation:
Given expression is 6ab−b
2
−2bc+12ac
It can be factorised as 6ab−b
2
−2bc+12ac=b(6a−b)+2c(6a−b)
Thus factors are (6a−b),(b+2c).
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