Math, asked by aryanthakkar45, 8 months ago

Factorise 6q^2+11q-7

Answers

Answered by kumarsatyam332000
1

Your answer6q

2

+11q−7

view step

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right)

x_{1}

x_{2}

ax^{2}+bx+c=0

6q^{2}+11q-7=0

6q

2

+11q−7=0

view step

ax^{2}+bx+c=0

\frac{-b±\sqrt{b^{2}-4ac}}{2a}

±

q=\frac{-11±\sqrt{11^{2}-4\times 6\left(-7\right)}}{2\times 6}

q=

2×6

−11±

11

2

−4×6(−7)

view step

11

q=\frac{-11±\sqrt{121-4\times 6\left(-7\right)}}{2\times 6}

q=

2×6

−11±

121−4×6(−7)

view step

-46

q=\frac{-11±\sqrt{121-24\left(-7\right)}}{2\times 6}

q=

2×6

−11±

121−24(−7)

view step

-24-7

q=\frac{-11±\sqrt{121+168}}{2\times 6}

q=

2×6

−11±

121+168

view step

121168

q=\frac{-11±\sqrt{289}}{2\times 6}

q=

2×6

−11±

289

view step

289

q=\frac{-11±17}{2\times 6}

q=

2×6

−11±17

view step

26

q=\frac{-11±17}{12}

q=

12

−11±17

view step

q=\frac{-11±17}{12}

±-1117

q=\frac{6}{12}

q=

12

6

view step

\frac{6}{12}=0.5

6

q=\frac{1}{2}

q=

2

1

view step

q=\frac{-11±17}{12}

±17-11

q=\frac{-28}{12}

q=

12

−28

view step

\frac{-28}{12}\approx -2.333333333

4

q=-\frac{7}{3}

q=−

3

7

view step

ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right)

\frac{1}{2}=0.5

x_{1}

-\frac{7}{3}\approx -2.333333333

x_{2}

6q^{2}+11q-7=6\left(q-\frac{1}{2}\right)\left(q-\left(-\frac{7}{3}\right)\right)

6q

2

+11q−7=6(q−

2

1

)(q−(−

3

7

))

view step

p-\left(-q\right)p+q

6q^{2}+11q-7=6\left(q-\frac{1}{2}\right)\left(q+\frac{7}{3}\right)

6q

2

+11q−7=6(q−

2

1

)(q+

3

7

)

view step

\frac{1}{2}=0.5

q

6q^{2}+11q-7=6\times \left(\frac{2q-1}{2}\right)\left(q+\frac{7}{3}\right)

6q

2

+11q−7=6×(

2

2q−1

)(q+

3

7

)

view step

\frac{7}{3}\approx 2.333333333

q

6q^{2}+11q-7=6\times \left(\frac{2q-1}{2}\right)\times \left(\frac{3q+7}{3}\right)

6q

2

+11q−7=6×(

2

2q−1

)×(

3

3q+7

)

view step

\frac{2q-1}{2}

\frac{3q+7}{3}

6q^{2}+11q-7=6\times \left(\frac{\left(2q-1\right)\left(3q+7\right)}{2\times 3}\right)

6q

2

+11q−7=6×(

2×3

(2q−1)(3q+7)

)

view step

23

6q^{2}+11q-7=6\times \left(\frac{\left(2q-1\right)\left(3q+7\right)}{6}\right)

6q

2

+11q−7=6×(

6

(2q−1)(3q+7)

)

view step

666

6q^{2}+11q-7=\left(2q-1\right)\left(3q+7\right)

6q

2

+11q−7=(2q−1)(3q+7)

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