Question

factorise:- 6x^2+20y^2+22xy

Answer 1

Hola Mate !!

Here's your answer :-

$6 {x}^{2} + 20 {y}^{2} + 22xy \\ = > 2(3 {x}^{2} + 10 {y}^{2} + 11xy) \\ = > 2(3 {x}^{2} + 11xy + 10 {y}^{2} ) \\ = > 2(3 {x}^{2} + 6x y+ 5 xy + 10 {y}^{2} ) \\ = > 2(3x(x + 2y) + 5y(x+ 2y)) \\ = > 2(x + y)(3x + 5y)$
Hope it helps
Mark me as brainliest if it's correct.

Answer 2

6x² + 22xy + 20y²
6x² + 10xy + 12xy + 20y²
2x(3x + 5y) + 4y(3x + 5y)
(2x + 4y) (3x + 5y)=0
x= -2y

or 3x = -5y