Question

factorise
6x^2-3-7x​

Answer 1

Answer:

6x²-7x-3

6x²-9x+2x-3

3x(2x-3)+1(2x-3)

(3x+1)(2x-3)

x=-1/3

x=3/2

Answer 2

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${\large{\purple{\mathbb{ANSWER}}}}$

☆ To factorize:-

• 6x²-3-7x

☆ Now,

=》 6x²-3-7x

= 6x²-7x-3

= 6x²-(9-2)x-3

= 6x²-9x+2x-3

= 3x(2x-3) + 1(2x-3)

${\large{\blue{\boxed{=\:\:(3x+1)\:(2x-3)}}}}$

☆ Hence factorized.

☆Solution:-

Now if (3x+1) And (2x-3) are the factors of the given eq. then

=》 (3x+1) (2x-3) = 0

=》 Either 3x+1 = 0

${\large{\orange{\boxed{=》\:\:x\:=\:-1/3}}}}$

Or,

=》 2x-3 = 0

${\large{\orange{\boxed{=》\:\:x\:=\:3/2}}}}$

Therefore the required value of x is -1/3 or 3/2.

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