factorise 6x^6 - 21x^4 - 12x^2
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Solution :
Given ,
6x^6 - 21x⁴ - 12x²
= 3x² [ 2x⁴ - 7x² - 4 ]
= 3x² [ 2x⁴ - 8x² + 1x² - 4 ]
= 3x² [ 2x²( x² - 4 ) + 1( x² - 4 ) ]
= 3x² [ ( x² - 4 )( 2x² + 1 ) ]
= 3x² [ ( x² - 2² )( 2x² + 1 ) ]
= 3x² ( x + 2 )( x - 2 )( 2x² + 1 )
••••
Given ,
6x^6 - 21x⁴ - 12x²
= 3x² [ 2x⁴ - 7x² - 4 ]
= 3x² [ 2x⁴ - 8x² + 1x² - 4 ]
= 3x² [ 2x²( x² - 4 ) + 1( x² - 4 ) ]
= 3x² [ ( x² - 4 )( 2x² + 1 ) ]
= 3x² [ ( x² - 2² )( 2x² + 1 ) ]
= 3x² ( x + 2 )( x - 2 )( 2x² + 1 )
••••
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