Question

Factorise 7√2x 2 -10x-4√2

Answer 1

Answer :

The factorized form of the given polynomial is :

{7√(2)x + 4}{x - √(2)}

Given :

The quadratic polynomial is :

• 7√(2)x² - 10x -4√(2)

To Find :

• The factorised form of the given polynomial :7√(2)x ² - 10x -4√(2)

Solution :

7√(2)x² - 10x - 4√(2)

= 7√(2)x² - 14x+ 4x - 4√(2)

= 7√(2)x{x - √(2)} + 4{x - √(2)}

= {7√(2)x + 4}{x - √(2)}

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If it would give to find the zeroes of this polynomial then :

7√(2)x + 4 = 0 and x -√(2) = 0

⇒x = -4/{7√(2)} and ⇒x = √(2)

⇒x = -4×√2/(7×2) and ⇒x = √(2)

⇒x = -4√2/14 and ⇒x = √(2)

⇒x = -2√2/7 and ⇒x = √(2)

Answer 2

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QUESTION :

Factorise 7√2x 2 -10x-4√2.

SOLUTION :

$7 \sqrt{2} {x}^{2} - 10x - 4 \sqrt{2}$

Let it be divided into two factors p and q ..

$pq \: = 7 \sqrt{2} \times 4 \sqrt{2} = 56$

$p + q \: = - 10$

So :

$p = 14 \\ \\ q = 4$

$= > 7 \sqrt{2} {x}^{2} - 10 x- 4 \sqrt{2} \\ \\ = > 7 \sqrt{2} {x}^{2} - 14x + 4x - 4\sqrt{2} \\ \\ = > 7x( \sqrt{2} x -1 ) + 2 \sqrt{2} ( \sqrt{2} x - 1) \\ = > (7x + 2 \sqrt{2} )( \sqrt{2} - 1)..... \: { \: a \: }$