Math, asked by komakshi14, 20 days ago

factorise 7mn-21m²n² ​

Answers

Answered by jkour0751
0

Answer:

TAKING OUT THE COMMON FACTORS

When each term of a given expression contains a common factor, divide each term by this factor and enclose the quotient within brackets, keeping the common factor outside the bracket.

Procedure:

* Find the H.C.F of all the terms of the given expression.

Eg: 6a^2-3ax =3a{6a^2/3a-3ax/3a} Ans=3a(2a-x)

GROUPING METHOD

An expression of an even number of terms, may be resolved into factors, if the terms are arranged in groups such that each group has a common factor.

Procedure:

*Group the terms of the given expression in such a way that each group has a common factor.

*Factorise each group formed.

*From each group, obtained in step 2, take out the common factor.

Eg: ab+bc+ax+cx

=(ab+bc)+(ax+cx)

=b(a+c)+x(a+c)

Ans=(a+c)(b+x)

Answered by jenishpatel56219
0
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