Question

factorise 8/27x³-1/8y³​

Answer 1

Answer:

8/27x³-1/8y³=(2/3x)^3-(1/2y)^3

=(2/3x-1/2y){(2/3x)^2(1/2y)^2+[(2/3x)(1/8y)]}

Answer 2

Answer:

$\frac{8}{27} {x}^{3} - \frac{1}{8} {y}^{3}$

$({ \frac{2x}{3} })^{3} - ( { \frac{y}{2} )}^{3}$

${( \frac{2x}{3} - \frac{y}{2}) }^{3} + 3 \times \frac{2x}{3} \times \frac{y}{2} ( \frac{2x}{3} - \frac{y}{2} )$

${( \frac{4x - 3y}{6} )}^{3} + xy( \frac{4x - 3y}{6} )$