Question

Factorise :
8 – 4l – 4m – 2lm – 4n + 2ln + 2mn – lmn
l is not 1 it is alphabet L
ans is:-
(2-l)(2-m)(2-n)

Answer 1

Step-by-step explanation:

given:4l2mn

to find:a.

Answer 2

The factors are $(2-n)(2-m)(2-l)$

Step-by-step explanation:

$8 - 4 l - 4 m + 2lm - 4n + 2ln + 2mn -lmn$

Taking two terms together, and bringing the common term outside the bracket in the same sequence as given:

8 – 4l – 4m – 2lm – 4n + 2ln + 2mn – lmn

$4(2 - l) - 2m(2-l) - 2n(2-l) + mn(2-l)$

We notice that the terms in the bracket are the same. SO, we can write the above equation as,

$(2 - l)(4 - 2m - 2n + mn)$

Again taking pairs of terms together

(2 -  l)(4 - 2m - 2n + mn)

So, common will be

$(2-l)${$2(2 - m) - n(2-m)$}

$(2-n)(2-m)(2-l)$