Math, asked by aster2004, 1 year ago

Factorise:
8(4x+5y)^2 - 12(4x+5y)

Answers

Answered by mysticd
164

Answer:

8(4x+5y)² - 12(4x+5y) = 4(4x+5y)(8x+10y-3)

Step-by-step explanation:

8(4x+5y)² - 12(4x+5y)

= 2×4(4x+5y)² - 3 × 4(4x+5y)

= 4(4x+5y) [ 2(4x+5y) - 3 ]

= 4(4x+5y)(8x+10y-3)

Therefore,

8(4x+5y)² - 12(4x+5y) = 4(4x+5y)(8x+10y-3)

Answered by vandanarajesh2008
25

Answer:

4(4x+5y)(8x+10y−3)

Step-by-step explanation:

Given: 8(4x+5y) 2 − 12(4x+5y)

⇒(4x+5y)[8(4x+5y)−12]

⇒4(4x+5y)[2(4x+5y)−3]

⇒4(4x+5y)[8x+10y−3]

⇒4(4x+5y)(8x+10y−3)

Similar questions