how can we solve maths puzzle
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In first 3 of the figure = 45
One figure = 15
Second a figure and two banana = 23
One banana = 23-15/2
→4
In third a banana and two clock= 10
One clock= 3
So forth add all we get 3+4+4*15
→7+60
→67
Thank you
One figure = 15
Second a figure and two banana = 23
One banana = 23-15/2
→4
In third a banana and two clock= 10
One clock= 3
So forth add all we get 3+4+4*15
→7+60
→67
Thank you
Answered by
1
Hello friend.
In the first one, 15+15+15 = 45 (45/3)(as all the three are equal)
Then 4+ 4 + 15 =23 (23-15=8) ( so equally shared 4 and 4)
Then, 4 + 3+3= 10 (10-4=6) ( so equally shared 3 and 3)
then, 3 + 4 + 4 x 15 = 3+4+60.( first u should solve multiplication - BODMAS)
then 7+60 = 67.
therefore 67 is the answer.
Hope it helps
please mark it as brainliest if you find it useful friend :-)
In the first one, 15+15+15 = 45 (45/3)(as all the three are equal)
Then 4+ 4 + 15 =23 (23-15=8) ( so equally shared 4 and 4)
Then, 4 + 3+3= 10 (10-4=6) ( so equally shared 3 and 3)
then, 3 + 4 + 4 x 15 = 3+4+60.( first u should solve multiplication - BODMAS)
then 7+60 = 67.
therefore 67 is the answer.
Hope it helps
please mark it as brainliest if you find it useful friend :-)
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