Question

Factorise 8 + 64x power 3

Answer 1

$8 + 64x {}^{3}$
We know that
$a {}^{3} + b {}^{3} = (a + b)(a {}^{2} - ab + b {}^{2} )$
So,
$(2) {}^{3} + (4x) {}^{3} \\ = (2 + 4x)( \: \: (2) {}^{2} - 2 \times 4x + (4x) {}^{2} \: ) \\ = (2 + 4x)(4 - 8x + 16x {}^{2})$

Answer 2

Answer:

the answer is above

hope this is helpful