6 minus x minus x square
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Answered by
1
6-x-x^2=0
Let take - as common
-(-6+x+x^2)=0
x^2+x-6=0
x^2+3x-2x-6=0
x (x+3)-2(x+3)=0
(x-2)(x+3)=0
x=2,-3
HOPE IT HELPS YOU
Thanks
Let take - as common
-(-6+x+x^2)=0
x^2+x-6=0
x^2+3x-2x-6=0
x (x+3)-2(x+3)=0
(x-2)(x+3)=0
x=2,-3
HOPE IT HELPS YOU
Thanks
Answered by
0
-[x^2+x-6]
-[x^2 -2x+3x-6]
-[x(x-2)+3(x-2)]
(x+3)(x-2)=0
x= -3,2
-[x^2 -2x+3x-6]
-[x(x-2)+3(x-2)]
(x+3)(x-2)=0
x= -3,2
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