Question

factorise 8 a cube minus b cube minus 4 ax +2 b x​

Answer 1

Answer:

HEY MATE HERE IS YOUR ANSWER

Answer 2

The factorization of the given expression is $(2a-b)(4a^2+b^2+2ab-2x)$ .

Explanation:

The given expression : $8a^3-b^3-4ax+2bx$

Since , $x^3-y^3=(x-y)(x^2+y^2+xy)$

Therefore ,  $8a^3-b^3=(2a^3)-b^3=(2a-b)((2a^2)+b^2+2ab)$

$=(2a-b)(4a^2+b^2+2ab)$

Now put this value in the given expression , we get

$8a^3-b^3-4ax+2bx=(2a-b)(4a^2+b^2+2ab) -2x(2a-b)$

Taking out (2a-b) as common, we get

$(2a-b)(4a^2+b^2+2ab-2x)$

Hence, the factorization of the given expression is $(2a-b)(4a^2+b^2+2ab-2x)$

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