Question

factorise 8 x cube y cube + 27 a cube​

Answer 1

8x³y³ + 27a³

=> (2xy)³ + (3a)³

As we know that :

a³ + b³ = (a + b)(a² - ab + b²)

Now,

=> (2xy + 3a)[(2xy)² - (2xy)(3a) + (3a)²]

=> (2xy + 3a)(4x²y² - 6xya + 97a²)

I hope it will be helpful for you ☺️

Fóllòw MË ❤️

Answer 2

$(2xy + 3a)( 4{x}^{2} {y}^{2} - 6xya + 9{a}^{3})$

Step-by-step explanation:

$8 {x}^{3} {y}^{3} + 27{a}^{3} \\ \\ = ({2xy})^{3} + ({3a})^{3} \\ \\ = (2xy + 3a){ ({2xy})^{2} - 2xy \times 3a + {3a}^{2} } \\ \\ (2xy + 3a)(4 {x}^{2} {y}^{2} - 6xya + 9{a}^{3})$

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