Math, asked by ac965410848772, 10 months ago

factorise 8 x cube + y cube + 27 Z cube minus 18 x y z​

Answers

Answered by fayazrahman4u
12

Answer:

(2x + y + 3z)[4x2 + y2 + 9z2 – 2xy – 3yz – 3zx]

Step-by-step explanation:

8x^3 + y^3 + 27^3 - 18xyz

= (2x)^3 + y^3 + (3z)^3 - 3 * 2x * y * 3z

=(2x + y + 3z)[4x2 + y2 + 9z2 – 2xy – 3yz – 3zx]          

Since, a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 +c^2 - ab -bc -ca)

Answered by Gillpubg
0

Step-by-step explanation:

sorry sorry first answer is

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