factorise 8 x cube + y cube + 27 Z cube minus 18 x y z
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Answer:
(2x + y + 3z)[4x2 + y2 + 9z2 – 2xy – 3yz – 3zx]
Step-by-step explanation:
8x^3 + y^3 + 27^3 - 18xyz
= (2x)^3 + y^3 + (3z)^3 - 3 * 2x * y * 3z
=(2x + y + 3z)[4x2 + y2 + 9z2 – 2xy – 3yz – 3zx]
Since, a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 +c^2 - ab -bc -ca)
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0
Step-by-step explanation:
sorry sorry first answer is
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