Factorise 81x square -198xy+121y square
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Answered by
55
Hi friend,
81x²-198xy+121y²=(9x)²-(2×9x×11y)+(11y)²=(9x-11y)²=(9x-11y)(9x-11y)
{as (a-b)²=a²-2ab+b²}
Hope this helps you...
81x²-198xy+121y²=(9x)²-(2×9x×11y)+(11y)²=(9x-11y)²=(9x-11y)(9x-11y)
{as (a-b)²=a²-2ab+b²}
Hope this helps you...
Answered by
23
81x^2 - 198xy + 121 y^2
=(9x)^2 -2×9x×11y + (11y)^2
=(9x-11y)^2 [as we know that (a-b)^2= a^2 -2ab +b^2]
Hope it helps
=(9x)^2 -2×9x×11y + (11y)^2
=(9x-11y)^2 [as we know that (a-b)^2= a^2 -2ab +b^2]
Hope it helps
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