factorise: 8a^3 + 27b^3
Answers
Answered by
2
Step-by-step explanation:
8a
3
+27b
3
=(2a)
3
+(3b)
3
=(2a+3b)(4a
2
+9b
2
−6ab)
[ x^3 + y^3 = (x+y) (x^2 + y^2 - xy)]
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Answered by
1
Answer:
\begin{gathered}8 {a}^{3} + 27 {b}^{3} \\ \\ = {(2a)}^{3} + {(3b)}^{3} \\ \\ = (2a + 3b)(4 {a}^{2} + 9 {b}^{2} - 6ab)\end{gathered}
8a
3
+27b
3
=(2a)
3
+(3b)
3
=(2a+3b)(4a
2
+9b
2
−6ab)
[ x^3 + y^3 = (x+y) (x^2 + y^2 - xy)]
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