Math, asked by thapahom044, 5 months ago

factorise
8a^3 - b^3​

Answers

Answered by anindyaadhikari13
3

Required Answer:-

Given to Factorise:

  • 8a³ - b³

Answer:

  • The factorised form is (2a - b)(4a² + 2ab + b²)

Solution:

 \sf 8 {a}^{3}  -  {b}^{3}

 \sf =  {(2a)}^{3}  -  {(b)}^{3}

It's in the form of x³ - y³. Factorise it.

 \sf = (2a - b)(4{a}^{2}  + 2ab +  {b}^{2} )

Hence, the factorised form is (2a - b)(4a² + 2ab + b²)

Identity Used:

  •  \sf {x}^{3}  -  {y}^{3}  = (x - y)( {x}^{2}  + xy +  {y}^{2} )

Other Identities:

  •  \sf {x}^{2}  + 2xy +  {y}^{2}  =  {(x + y)}^{2}
  •  \sf {x}^{2} -  2xy +  {y}^{2}  =  {(x - y)}^{2}
  •  \sf {x}^{2}  -  {y}^{2}  = (x + y)(x - y)
  •  \sf {x}^{3} + {y}^{3}  = (x + y)( {x}^{2} - xy +  {y}^{2} )
Answered by Anisha5119
4

Answer:

Heya mate here's the answer Mark as brainliest pleaseeeeee follow

Attachments:
Similar questions