Question

factorise 8a^3 - b^3 - 4 ax +2 bx
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Answer 1

Step-by-step explanation:

8a³-b³ -2x(2a-b)

(2a)³ -b³-2x(2a-b)

(2a-b){(2a)²+2a×b+b²)-2x(2a-b)

Formula[a³-b³=(a-b)(a²+ab+b²)]

(2a-b)(4a²+2ab+b²)-2x(2a-b)

(2a-b)(4a²+2ab+b²-2x)

8a³-b³-4ax+2bx

ANS::(2a-b)(4a²+2ab+b²-2x)

Hope it helps...

Thank you...