Question

find the point on x- axis which is equidistant from A( 4 - 3) and B( 0, 11)

chapter 7 class 10​

Answer 1

answer:

Given : points A(6,3) and B(-1,4)

To find : point on x-axis which is equidistant from A(6,3) and B(-1,4)

 

let the point lying on x axis to be found be given by C (x,0)  

 

as C is equidistant from A and B  

=> AC = BC  

squaring both the sides

=> AC2 = BC2  

using the distance formula ((x2-x1)2 + (y2-y1)2)   { squared of it }

 

=> ( 6 - x )2 + (3-0)2  = (x-(-1))2 +( 0-4)2

=> 36 + x2 - 12 x + 9 = x2 + 1 + 2x + 16 { using (a-b)2 = a2+b2 -2ab }

 

=> 14x = 28

=> x= 2

hope this will help u:)

Answer 2

Answer:

refer to the attachment:::