factorise 8a²(a-b)²-4a²(a-b)³
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Solution:
8a²b(a-b)²-4a²(a-b)³
= 4a²(a-b)²[ 2b - (a-b)]
= 4a²(a-b)²( 2b-a+b)
= 4a²(a-b)²(3b-a)
Therefore,
8a²b(a-b)²-4a²(a-b)³
= 4a²(a-b)²(3b-a)
••••
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:
4²(–)²(3–)
▀▄▀▄Step by step explanation▄▀▄▀
◦•●◉✿4a²(a–b)²[2b-(a-b)]✿◉●•◦
◦•●◉✿4a²(a-b)²(3b-a)✿◉●•◦
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