Question

Factorise- 8a³-27b³​

Answer 1

Step-by-step explanation:

• 8a3 -27b3
• (2a)3 - (3b)3

Answer 2

Answer:

After factorization $8a^3 - 27b^3$ we get  (2a - 3b)($4a^2 + 6ab + 9b^2$) as result.

Step-by-step explanation:

Explanation:

Given that, $8a^3 - 27 b^3$

As we know that, $2^3$ = 8 and $3^3$ = 27.

So, $8a^3 - 27 b^3$ can be written as,

⇒ $(2a)^3 - (3b)^3$

Step 1:

Now, we know that $a^3 - b^3 = (a -b)(a^2 + ab + b^2)$.

So, from the question we have,

a = 2a and b = 3b

Therefore, on applying the formula of $a^3 - b^3$ we get,

⇒$(2a)^3 - (3b)^3$

⇒ (2a - 3b)($(2a)^2 + (2a)(3b) + (3b)^2$)

⇒ (2a - 3b)($4a^2 + 6ab + 9b^2$)

Final answer:

Hence,  (2a - 3b)($4a^2 + 6ab + 9b^2$) is the required value.

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