If x-1 and x+3 are the factors of the polynomial x^3-ax^2-13x-b, then find the values of a and b.
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if x-1 and x+3 are factors of the given question
then 1,-3 will satisfying the equation
putting 1 and -3 in the given equation in place of x. we have
put x=1
1-a-13-b=0
a+b=-12
putting x=-3
-27-9a+39-b=0
9a+b=12
a+b=-12
10a=0
a=0
b=-12
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