Math, asked by Zuhatambolixyz, 11 months ago

factorise 8a3-27b3
with explanation​

Answers

Answered by yuvraj309644
3

8a3-27b3

(2a)^3 - (3b)^3

using identity

a^3-b^3 = (a-b) ( a^2 + b^2 + ab)

(2a - 3b) ( 4a^2 + 9b^2 + 6ab)

I hope It will help you.

Answered by alok200648
4

Step-by-step explanation:

8a³-27b³

=(2a)³-(3b)³

=(2a-3b) ((2a)²+2a×3b+(3b)²)

=(2a-3b) (4a²+6ab+9b²)

I hope this will help you.

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