Question

Factorise: 8a³-b³-12a²b+6ab²​

Answer 1

Answer:

8a^3-b^3-12a^2b+6ab^2

=(2a)^3-(b)^3-6ab(2a-b)

=(2a-b){(2a)^2+2a.b+b^2}-6ab(2a-b)

=(2a-b)(4a^2+2ab+b^2)-6ab(2a-b)

=(2a-b)(4a^3+2ab+b^2-6ab)

=(2a-b)(4a^2-4ab+b^2)

=(2a-b){(2a)^2-2.2a.b+(b)^2}

=(2a-b)(2a-b)^2

=(2a-b)^3

Answer 2

here is ur answer

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