Factorise 8a3-b3-12a2b-6ab2 and write the identity used
Answers
Answered by
68
8a3-b3-12a2b-6ab2
=(-2a)3- (b)3- 3 (-2a)2*b+ 3*(-2a)*b
by using identity (a-b)^3
we get,
= (-2a-b)^3
=(-2a)3- (b)3- 3 (-2a)2*b+ 3*(-2a)*b
by using identity (a-b)^3
we get,
= (-2a-b)^3
inchara32:
using identity u find please
please please
Answered by
46
Step-by-step explanation:
8a3+b3+12a2b+6ab2
=(x+y)3=x3+y3+3x2y+3xy2
=(2a) 3 + b3+3 <2a>2 (b) +3 (2a) -(b) 2
=(2a+b)3
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