Question

Factorise 8acube+ bcube+12asquareb+ 6absquare

Answer 1

Answer:

Refer below for answer

$8 {a}^{3} + {b}^{3} + 12 {a}^{2} b + 6ab {}^{2} \\ = ({2a})^{3} + {b}^{3} + 3( {2a}^{2} )(b) + 3(2a)( {b) }^{2} \\ (x + y)^{3} = x {}^{3} + {y}^{3} + 3 {x}^{2} y + 3x {y}^{2} \\ = (2a + b) {}^{3}$

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