Factorise 8p^3-q^3-12p^2q+6pq^2
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Answered by
28
8p^3-q^3-12p^2q+6pq^2
= (2p)^3 - (q)^3 -3(2p)^2(1)-3(2p)(q)^2
= (2p-q)^3
= (2p)^3 - (q)^3 -3(2p)^2(1)-3(2p)(q)^2
= (2p-q)^3
kunal0912:
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byee
Answered by
23
8p^3-q^3-12p^2q+6pq^2
=(2p)^3-q^3-3*(2p)^2*q+3*2p*q
=(2p+q)^3
(a+b)^3=a^3+b^3+a^2*b+a*b^2
=(2p)^3-q^3-3*(2p)^2*q+3*2p*q
=(2p+q)^3
(a+b)^3=a^3+b^3+a^2*b+a*b^2
this is the answer which i needed
thanks a lot bro
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