Factorise 8x^3+27y^3
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Answered by
27
8x^3+27y^3=> (2x)^3+(3y)^3
=> (2x+3y)[(2x)^2-(2x)(3y)+(3y^2)]
=> (2x+3y)(4x^2-6xy+9y^2)
ans
=> (2x+3y)[(2x)^2-(2x)(3y)+(3y^2)]
=> (2x+3y)(4x^2-6xy+9y^2)
ans
mysticd:
Plz , implies symbol as =
And write the identity
yeah ur right
:)
Answered by
26
It's (2x)^3+(3y)^3
a^3+b^3=(a+b)(a^2_ab+b^2)
Here
(2x+3y)(4x^2-6xy+9y^2)
a^3+b^3=(a+b)(a^2_ab+b^2)
Here
(2x+3y)(4x^2-6xy+9y^2)
good
Thankss
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