Factorise:- 8x^3 -(2x-y)^3
Answers
Answered by
10
8x^3-(2x-y)^3
=(2x)^3 - (2x-y)^3
=(2x-2x+y)(4x^2+4x^2-2xy+4x^2-4xy+y^2)
=y(12x^2-6xy+y^2)
=(2x)^3 - (2x-y)^3
=(2x-2x+y)(4x^2+4x^2-2xy+4x^2-4xy+y^2)
=y(12x^2-6xy+y^2)
Answered by
2
let the 8x^3 = a
and = (2x-y)=b
therefore : a^3 -b^3= (a-b)(a^2+b^2+ab)
= (8x-2x-y)(64x^2 +y^2 +16x^×- 8y)
and = (2x-y)=b
therefore : a^3 -b^3= (a-b)(a^2+b^2+ab)
= (8x-2x-y)(64x^2 +y^2 +16x^×- 8y)
Similar questions