Question

factorise:8x^cube+rout64ychub

Answer 1

Hi.

This can be factorized using the following identity:

$a^3+b^3 = (a+b)(a^2-ab+b^2)$

$8x^3 + 64y^3\\\\= (2x)^3 + (4y)^3\\\\= (2x+4y)((2x)^2 - (2x)(4y) + (4y)^2)\\\\= (2x+4y)(4x^2 - 8xy + 16y^2)$

Hope it helps.