Factorise 8x3-27y3+125+90xy
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Answered by
5
That's easy . It would be done like this:
8x^3+27y^3+125+90xy
=(2x)^3+(3y)^3+(5)^3+3*2x*3y*5
Then using Identity 8 it would be;
(2x+3y+5)^3
8x^3+27y^3+125+90xy
=(2x)^3+(3y)^3+(5)^3+3*2x*3y*5
Then using Identity 8 it would be;
(2x+3y+5)^3
Answered by
1
Answer:
Step-by-step explanation:
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