factorise 8ycube-125xcube
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8Y^3 - 125 X^3
(2Y) ^3 - (5x)^3
it is an identity
a^3 - b^3 = (a-b) ( a^2 + ab + b^2)
(2y)^3 -( 5y) ^3 = (2y - 5x) [ (2y) ^2 + (2y) (5 x) + (5x) ^2]
= (2y - 5x ) ( 4 y ^2 + 10 xy + 25 x^2)
(2Y) ^3 - (5x)^3
it is an identity
a^3 - b^3 = (a-b) ( a^2 + ab + b^2)
(2y)^3 -( 5y) ^3 = (2y - 5x) [ (2y) ^2 + (2y) (5 x) + (5x) ^2]
= (2y - 5x ) ( 4 y ^2 + 10 xy + 25 x^2)
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