Math, asked by shabdsingla13, 10 months ago

factorise
9(2a-b)^2-4(2a-b)-13

Answers

Answered by kanekeikenghoul
1

Answer:

(18a – 9b – 13)(2a – b + 1)

Step-by-step explanation:

9 × (2a – b)² – 4 × (2a – b) – 13

[Let (2a – b) be a]

= 9a² – 4a – 13

= 9a² – 13a + 9a – 13   {Middle term break}

= a(9a – 13) + (9a – 13)

= (9a – 13)(a + 1)

[Putting the value of a back]

= [9(2a – b) – 13)[ (2a – b) + 1]

= (18a – 9b – 13)(2a – b + 1).

Hope it helps...please mark as brainliest.

Answered by soumyashree96
0

go through the picture and see the answer

I hope it help you

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