factorise
9(2a-b)^2-4(2a-b)-13
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Answer:
(18a – 9b – 13)(2a – b + 1)
Step-by-step explanation:
9 × (2a – b)² – 4 × (2a – b) – 13
[Let (2a – b) be a]
= 9a² – 4a – 13
= 9a² – 13a + 9a – 13 {Middle term break}
= a(9a – 13) + (9a – 13)
= (9a – 13)(a + 1)
[Putting the value of a back]
= [9(2a – b) – 13)[ (2a – b) + 1]
= (18a – 9b – 13)(2a – b + 1).
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