Question

factorise 9 (2a-b)^2-4 (2a-b)-13​

Answer 1

Answer:

-1 and 13/9

Step-by-step explanation:

so....

lets take 2a-b = t

then our equation becomes, 9t²-4t-13=0,

now we'r gonna factorise aur new equation,..

=>9t²+9t-13t-13 =0

=>9t(t+1) -13(t+1) =0

=> (9t-13) (t+1) = 0

from here, we get,

t= -1 and 13/9

putting back t = 2a-b

so we are getting,

2a-b = -1 and 2a-b = 13/9

therefore.....factors of the question equation are -1 and 13/9...☺️☺️☺️☺️

Hope Brother.....i m clear to you.....

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Jai Hind